Key Gas Law Equations to Know for AP Physics 2 (2025) (AP)

What You Need to Know

Gas-law questions in AP Physics 2 are mostly about connecting macroscopic variables—pressure PP, volume VV, temperature TT, amount of gas nn (moles) or NN (molecules)—and using those relationships to predict what changes when the gas is heated, compressed, mixed, or moved through a thermodynamic process.

The “big idea” you lean on repeatedly:

  • Ideal Gas Model (works well for low-density gases):
    PV=nRT=NkBTPV = nRT = Nk_B T

If you know when you can treat nn as constant (sealed container) vs changing (adding/removing gas), and you keep units consistent (especially **Kelvin** for TT), you’ll be able to handle most AP-style gas-law setups.

Critical reminder: Temperature in gas laws is always absolute temperature: TK=TC+273.15T_{K} = T_{\circ C} + 273.15.


Step-by-Step Breakdown

A. Choosing the right gas-law equation (fast decision tree)
  1. List what’s given and what changes: identify P1,V1,T1,n1P_1, V_1, T_1, n_1 and P2,V2,T2,n2P_2, V_2, T_2, n_2.
  2. Decide if the amount of gas is constant:
    • Sealed container (no leaks, no gas added): nn constant.
    • Open system, adding gas, chemical reaction producing gas: nn changes.
  3. Pick the simplest law:
    • If TT constant (isothermal): use Boyle’s: P1V1=P2V2P_1 V_1 = P_2 V_2.
    • If PP constant (isobaric): use Charles’s: V1T1=V2T2\frac{V_1}{T_1} = \frac{V_2}{T_2}.
    • If VV constant (isochoric): use Gay-Lussac’s: P1T1=P2T2\frac{P_1}{T_1} = \frac{P_2}{T_2}.
    • If nn constant but multiple variables change: use combined gas law:
      P1V1T1=P2V2T2\frac{P_1 V_1}{T_1} = \frac{P_2 V_2}{T_2}
    • If nn not constant (or you want a one-step universal setup): use ideal gas law:
      PV=nRTPV = nRT.
  4. Convert units early:
    • TT to Kelvin.
    • PP to Pa if you’re using R = 8.314\,\text{J/(mol·K)}.
    • VV to m3\text{m}^3 for SI.
  5. Solve algebraically before plugging numbers (reduces mistakes).
B. Partial pressures (mixtures) procedure
  1. Determine which law applies:
    • For mixtures of ideal gases: Dalton’s law: Ptot=iPiP_{\text{tot}} = \sum_i P_i.
  2. If you know moles, use mole fraction:
    • xi=nintotx_i = \frac{n_i}{n_{\text{tot}}} and Pi=xiPtotP_i = x_i P_{\text{tot}}.
  3. If gas is collected over water (common lab context):
    • Pgas=PtotPH2OP_{\text{gas}} = P_{\text{tot}} - P_{\text{H}_2\text{O}}.
Quick worked mini-example (method in action)

A sealed syringe: V1=30mLV_1 = 30\,\text{mL}, P1=1.0atmP_1 = 1.0\,\text{atm}, compressed to V2=10mLV_2 = 10\,\text{mL} at constant TT. Find P2P_2.

  • Constant TT and constant nn → Boyle’s law: P1V1=P2V2P_1V_1=P_2V_2.
  • Solve: P2=P1V1V2=(1.0atm)3010=3.0atmP_2 = P_1\frac{V_1}{V_2} = (1.0\,\text{atm})\frac{30}{10} = 3.0\,\text{atm}.

Key Formulas, Rules & Facts

Core gas laws (macroscopic relationships)
RelationshipFormulaWhen to useNotes
Ideal Gas LawPV=nRTPV = nRTUniversal go-to for ideal gasesWorks best at low PP, high TT; use consistent units
Molecular formPV=NkBTPV = Nk_B TWhen given molecules, not molesN=nNAN = nN_A
Combined Gas LawP1V1T1=P2V2T2\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}Sealed sample (constant nn) with multiple changesDerived from Boyle/Charles/Gay-Lussac
Boyle’s LawP1V1=P2V2P_1V_1=P_2V_2Constant TT and nnInverse: P1VP \propto \frac{1}{V}
Charles’s LawV1T1=V2T2\frac{V_1}{T_1}=\frac{V_2}{T_2}Constant PP and nnDirect: VTV \propto T
Gay-Lussac’s LawP1T1=P2T2\frac{P_1}{T_1}=\frac{P_2}{T_2}Constant VV and nnDirect: PTP \propto T
Avogadro’s LawV1n1=V2n2\frac{V_1}{n_1}=\frac{V_2}{n_2}Constant PP and TTDirect: VnV \propto n
Constants + unit anchors (know these cold)
ConstantValueUse
Ideal gas constant (SI)R = 8.314\,\text{J/(mol·K)}Best with PP in Pa and VV in m3\text{m}^3
Ideal gas constant (atm·L)R = 0.08206\,\text{L·atm/(mol·K)}Only if everything is in atm and L
Boltzmann constantkB=1.381×1023J/Kk_B = 1.381\times 10^{-23}\,\text{J/K}Microscopic form PV=NkBTPV=Nk_BT
Avogadro’s numberNA=6.022×1023mol1N_A = 6.022\times 10^{23}\,\text{mol}^{-1}Converts nNn \leftrightarrow N
Atmosphere to pascal1atm=1.013×105Pa1\,\text{atm} = 1.013\times 10^5\,\text{Pa}Pressure conversion
Liter to cubic meter1L=103m31\,\text{L} = 10^{-3}\,\text{m}^3Volume conversion
Gas mixtures (Dalton’s law)
RuleFormulaWhen to useNotes
Dalton’s lawPtot=iPiP_{\text{tot}} = \sum_i P_iMixture of nonreacting ideal gasesEach gas “acts alone”
Partial pressure via mole fractionPi=xiPtotP_i = x_i P_{\text{tot}}, xi=nintotx_i = \frac{n_i}{n_{\text{tot}}}Given moles/ratiosSame TT and VV for all gases in mixture
Gas over water correctionPdry=PtotPH2OP_{\text{dry}}=P_{\text{tot}}-P_{\text{H}_2\text{O}}Collection over waterPH2OP_{\text{H}_2\text{O}} depends on temperature
Kinetic theory connections (often tested conceptually + quantitatively)
IdeaFormulaWhat it tells youNotes
Mean translational KE (per molecule)K=32kBT\langle K \rangle = \frac{3}{2}k_BTTemperature measures average molecular KEIndependent of gas type
Mean translational KE (per mole)Kmol=32RT\langle K \rangle_{\text{mol}} = \frac{3}{2}RTSame idea, per moleUseful with nn
RMS speedvrms=3kBTm=3RTMv_{\text{rms}}=\sqrt{\frac{3k_BT}{m}}=\sqrt{\frac{3RT}{M}}Typical molecular speedmm = mass per molecule, MM = molar mass in kg/mol\text{kg/mol}
Pressure–speed relationP=13ρvrms2P=\frac{1}{3}\rho v_{\text{rms}}^2Links macroscopic PP to microscopic motionρ\rho is mass density
Internal energy for ideal gases (ties gas laws to thermodynamics)
Gas modelInternal energy UUWhen usedNotes
Ideal gas (general)U=f2nRTU=\frac{f}{2}nRTIf degrees of freedom ff given/assumedDepends only on TT for ideal gas
Monatomic ideal gasU=32nRTU=\frac{3}{2}nRTCommon AP assumptionf=3f=3
Diatomic (room temp approx.)U52nRTU\approx\frac{5}{2}nRTSometimes usedRotational modes active, vibrational often ignored
Common “process” equations that pair with ideal gas law

These show up when a problem describes a thermodynamic path (even if it calls it “gas law” reasoning).

ProcessConditionKey relationNotes
IsothermalTT constantPV=constPV=\text{const}Same as Boyle for ideal gas
IsobaricPP constantVT=const\frac{V}{T}=\text{const}Same as Charles
IsochoricVV constantPT=const\frac{P}{T}=\text{const}Same as Gay-Lussac
Adiabatic (ideal gas)Q=0Q=0PVγ=constPV^{\gamma}=\text{const}Typically beyond “simple” gas laws, but shows up in AP thermodynamics; γ=CPCV\gamma=\frac{C_P}{C_V}

If you’re not explicitly told the process (isothermal, etc.), don’t assume it—use what’s stated about what is held constant.


Examples & Applications

Example 1: Combined gas law (sealed sample)

A sealed can of air: P1=2.0×105PaP_1=2.0\times 10^5\,\text{Pa}, T1=300KT_1=300\,\text{K}. It’s heated to T2=450KT_2=450\,\text{K} with constant volume. Find P2P_2.

  • Constant VV and nnPT=const\frac{P}{T}=\text{const}.
  • P2=P1T2T1=(2.0×105)450300=3.0×105PaP_2 = P_1\frac{T_2}{T_1} = (2.0\times 10^5)\frac{450}{300} = 3.0\times 10^5\,\text{Pa}.

AP-style insight: at fixed VV, pressure scales linearly with absolute temperature.

Example 2: Ideal gas law to find moles (units trap)

A scuba tank has V=12LV=12\,\text{L}, P=2.0×107PaP=2.0\times 10^7\,\text{Pa}, T=300KT=300\,\text{K}. How many moles of air? (Treat as ideal.)

  • Convert volume: V=12×103m3V = 12\times 10^{-3}\,\text{m}^3.
  • Use PV=nRTPV=nRT:
    n=PVRT=(2.0×107)(12×103)(8.314)(300)96moln=\frac{PV}{RT}=\frac{(2.0\times 10^7)(12\times 10^{-3})}{(8.314)(300)}\approx 96\,\text{mol}.

Exam angle: The hard part is usually not algebra—it’s consistent SI units.

Example 3: Dalton’s law + mole fraction

A container at TT and VV holds nHe=1.0moln_{\text{He}}=1.0\,\text{mol} and nNe=3.0moln_{\text{Ne}}=3.0\,\text{mol}. Total pressure is Ptot=400kPaP_{\text{tot}}=400\,\text{kPa}. Find PHeP_{\text{He}}.

  • Mole fraction: xHe=1.01.0+3.0=0.25x_{\text{He}}=\frac{1.0}{1.0+3.0}=0.25.
  • Partial pressure: PHe=xHePtot=(0.25)(400kPa)=100kPaP_{\text{He}}=x_{\text{He}}P_{\text{tot}}=(0.25)(400\,\text{kPa})=100\,\text{kPa}.

AP-style insight: partial pressures depend on mole fractions, not molar masses.

Example 4: RMS speed comparison (temperature + molar mass)

At the same TT, compare vrmsv_{\text{rms}} for helium (molar mass MHe=0.004kg/molM_{\text{He}}=0.004\,\text{kg/mol}) and nitrogen (MN2=0.028kg/molM_{\text{N}_2}=0.028\,\text{kg/mol}).

  • vrms1Mv_{\text{rms}}\propto \frac{1}{\sqrt{M}} at fixed TT.
  • Ratio:
    vrms,Hevrms,N2=MN2MHe=0.0280.004=72.65\frac{v_{\text{rms,He}}}{v_{\text{rms,N}_2}}=\sqrt{\frac{M_{\text{N}_2}}{M_{\text{He}}}}=\sqrt{\frac{0.028}{0.004}}=\sqrt{7}\approx 2.65.

Common exam prompt: “Which gas has higher typical molecular speed at the same temperature?” (Lighter molar mass → faster.)


Common Mistakes & Traps

  1. Forgetting Kelvin (using TCT_{\circ C} directly)
    What goes wrong: You’ll predict the wrong proportional changes (sometimes even negative temperatures).
    Fix: Always convert with TK=TC+273.15T_K = T_{\circ C}+273.15.

  2. Mixing unit systems for RR
    What goes wrong: Using R=8.314R=8.314 with PP in atm and VV in L gives nonsense.
    Fix: Either go full SI (Pa, m3\text{m}^3, K, R=8.314R=8.314) or full atm·L (atm, L, K, R=0.08206R=0.08206).

  3. Using the combined gas law when nn changes
    What goes wrong: PVT\frac{PV}{T} is only constant if nn is constant.
    Fix: If gas can enter/leave or moles change, use PV=nRTPV=nRT with explicit nn.

  4. Assuming “constant pressure” just because the container is open
    What goes wrong: In an open container, the gas can exchange with the environment, but the details matter; pressure may be atmospheric, but the amount of gas may change.
    Fix: Write what you know: if truly open to atmosphere, you can often take PPatmP\approx P_{\text{atm}}, but then nn is not fixed.

  5. Confusing partial pressure with “fraction of volume” in non-identical conditions
    What goes wrong: Pi=xiPtotP_i=x_iP_{\text{tot}} assumes a well-mixed ideal gas at common TT and VV.
    Fix: Only use mole fraction relations when the mixture shares the same container (same TT, VV).

  6. Using molar mass in g/mol\text{g/mol} inside vrmsv_{\text{rms}}
    What goes wrong: A factor of 1000\sqrt{1000} error in speed.
    Fix: In vrms=3RTMv_{\text{rms}}=\sqrt{\frac{3RT}{M}}, MM must be in kg/mol\text{kg/mol}.

  7. Thinking “higher pressure means higher temperature” (without constraints)
    What goes wrong: Pressure can increase due to decreased volume at constant temperature (Boyle).
    Fix: Always state which variables are held constant before inferring relationships.

  8. Sign errors and conceptual slips with “compression” and “expansion”
    What goes wrong: You might invert ratios like V1V2\frac{V_1}{V_2}.
    Fix: Do a quick sanity check: compressing means V2<V1V_2<V_1, so at constant TT, P2>P1P_2>P_1.


Memory Aids & Quick Tricks

Trick / mnemonicWhat it helps you rememberWhen to use it
K for KelvinAlways use absolute temperatureAny gas law problem
B-C-G” (Boyle–Charles–Gay-Lussac)Which variable pairs with TT depending on what’s constantQuick identification of simple laws
Same TT → same average KEK=32kBT\langle K \rangle = \frac{3}{2}k_BT depends only on TTKinetic theory / conceptual MCQ
Lighter → fastervrms1/Mv_{\text{rms}}\propto 1/\sqrt{M}RMS speed comparisons
Parts add to wholePtot=PiP_{\text{tot}}=\sum P_iDalton’s law mixture problems
Ratio sanity checkIf VV decreases and TT fixed, PP must increaseAvoid algebra flips in Boyle/combined

Quick Review Checklist

  • You can write and use PV=nRTPV=nRT and know what each symbol means.
  • You automatically convert to Kelvin: TK=TC+273.15T_K=T_{\circ C}+273.15.
  • You keep units consistent with your chosen RR (SI vs atm·L).
  • You know when PVT\frac{PV}{T} is constant: only when nn is constant.
  • You can recognize special cases:
    • Isothermal: P1V1=P2V2P_1V_1=P_2V_2
    • Isochoric: P1T1=P2T2\frac{P_1}{T_1}=\frac{P_2}{T_2}
    • Isobaric: V1T1=V2T2\frac{V_1}{T_1}=\frac{V_2}{T_2}
  • You can do mixture problems with Dalton’s law: Ptot=PiP_{\text{tot}}=\sum P_i and Pi=xiPtotP_i=x_iP_{\text{tot}}.
  • You can connect microscopic and macroscopic ideas:
    • K=32kBT\langle K \rangle = \frac{3}{2}k_BT
    • vrms=3RTMv_{\text{rms}}=\sqrt{\frac{3RT}{M}} (with MM in kg/mol\text{kg/mol})
  • You do a quick sanity check: compress → PP up (if TT constant), heat at constant VVPP up.

You’ve got this—gas laws are mostly pattern recognition plus clean units.