AP Calculus BC Unit 10: Convergence Tests for Infinite Series

0.0(0)
Studied by 0 people
0%Unit 10 Mastery
0%Exam Mastery
Build your Mastery score
multiple choiceAP Practice
Supplemental Materials
call kaiCall Kai
Card Sorting

1/24

Last updated 3:08 PM on 3/12/26
Name
Mastery
Learn
Test
Matching
Spaced
Call with Kai

No analytics yet

Send a link to your students to track their progress

25 Terms

1
New cards

Convergence test

A method for deciding whether an infinite series has a finite sum (converges) or does not settle to a finite value (diverges).

2
New cards

Infinite series

An expression of the form an\sum a_n representing the sum of infinitely many terms, interpreted as the limit of its partial sums.

3
New cards

Converges

A series converges if its sequence of partial sums approaches a finite limit.

4
New cards

Diverges

A series diverges if its partial sums do not approach a finite limit (may grow without bound or oscillate without settling).

5
New cards

Integral Test

A test stating that if an=f(n)a_n = f(n) where f is positive, continuous, and decreasing on [1,)[1,\infty), then an\sum a_n and 1f(x)dx\int_1^\infty f(x)\,dx either both converge or both diverge.

6
New cards

Improper integral (to infinity)

An integral with an infinite limit of integration, evaluated using a limit: 1f(x)dx=limb1bf(x)dx\int_1^\infty f(x)\,dx = \lim_{b\to\infty} \int_1^b f(x)\,dx.

7
New cards

Conditions for the Integral Test

The function f(x) must be positive, continuous, and decreasing for x \ge 1, and satisfy an=f(n)a_n = f(n).

8
New cards

Partial sum (S_N)

The finite sum of the first N terms of a series: SN=n=1NanS_N = \sum_{n=1}^N a_n.

9
New cards

Series sum (S)

If a series converges, its sum S is the limit of partial sums: S=limNSNS = \lim_{N\to\infty} S_N.

10
New cards

Remainder / error (R_N)

The difference between the true sum and the Nth partial sum: RN=SSNR_N = S - S_N.

11
New cards

p-series

A benchmark series of the form n=11/np\sum_{n=1}^\infty 1/n^p, which converges if p > 1 and diverges if p1p \le 1.

12
New cards

Harmonic series

The series n=11/n\sum_{n=1}^\infty 1/n, a p-series with p = 1 that diverges.

13
New cards

Geometric series

A series of the form n=0arn\sum_{n=0}^\infty a r^n, which converges if |r| < 1 (and diverges if r1|r| \ge 1).

14
New cards

Direct Comparison Test

If 0anbn0 \le a_n \le b_n and bn\sum b_n converges, then an\sum a_n converges; if 0bnan0 \le b_n \le a_n and bn\sum b_n diverges, then an\sum a_n diverges.

15
New cards

Limit Comparison Test

For positive terms, compute L=limn(an/bn)L = \lim_{n\to\infty} (a_n/b_n). If 0<L<0 < L < \infty, then an\sum a_n and bn\sum b_n either both converge or both diverge.

16
New cards

Inconclusive (Limit Comparison)

If L = 0 or L = \infty in the Limit Comparison Test, the test does not determine convergence/divergence.

17
New cards

Dominant term (for comparisons)

The leading/most significant part of an expression for large n (often highest power of n) used to choose a comparison series bnb_n.

18
New cards

Alternating series

A series whose terms change sign, often written as (1)n1bn\sum (-1)^{n-1} b_n or (1)nbn\sum (-1)^n b_n with bn0b_n \ge 0.

19
New cards

Alternating Series Test (Leibniz Test)

An alternating series (1)n1bn\sum (-1)^{n-1} b_n converges if bnb_n is eventually decreasing and bn0b_n \to 0 as nn \to \infty.

20
New cards

nth-term divergence idea

If limnan0\lim_{n\to\infty} a_n \ne 0 (or does not exist), then the series an\sum a_n must diverge.

21
New cards

Alternating Series Error Bound

If the Alternating Series Test applies, then the error after N terms satisfies RNbN+1|R_N| \le b_{N+1} (the next term’s magnitude).

22
New cards

Tolerance (alternating approximation)

A desired maximum error; for alternating series you choose N so that bN+1b_{N+1} < tolerance.

23
New cards

Conditional convergence

A series that converges, but its series of absolute values diverges (often occurs with alternating series).

24
New cards

Absolute convergence

A series an\sum a_n converges absolutely if an\sum |a_n| converges.

25
New cards

Ratio Test

Compute L=limnan+1/anL = \lim_{n\to\infty} |a_{n+1}/a_n|. If L < 1 the series converges absolutely; if L > 1 (or L=L = \infty) it diverges; if L = 1 it is inconclusive.