Gravitational Field Equations to Know for AP Physics 1 (2025)

What You Need to Know

Gravitational field equations let you connect mass distributions to forces, accelerations, and energies. On AP Physics 1, they show up in:

  • Attraction between masses (Newton’s law of gravitation)
  • Weight vs. mass and how gg changes with altitude
  • Orbits (circular motion + gravity)
  • Gravitational potential energy (near Earth and universal)

Core idea: a mass creates a gravitational field g\vec g that pulls other masses toward it. The field is defined by:

gFgm\vec g \equiv \frac{\vec F_g}{m}

So if you know g\vec g at a location, the gravitational force on a mass mm there is:

Fg=mg\vec F_g = m\vec g

AP Physics 1 focus: You do algebra-based gravitation: point masses / spherical bodies, inverse-square relationships, energy, and circular orbits. No calculus-based field integrals.


Step-by-Step Breakdown

Use this process whenever you see “gravitational force,” “field,” “weight at altitude,” or “orbit.”

1) Decide which model applies
  1. Near Earth (constant field): Use Fg=mgF_g = mg and Ug=mghU_g = mgh when height changes are small relative to Earth’s radius.
  2. Universal gravitation (inverse-square): Use Fg=Gm1m2r2F_g = \frac{Gm_1m_2}{r^2} and g=GMr2g = \frac{GM}{r^2} when distances are large (satellites/planets) or gg is changing.
  3. Orbital motion: If something is in (circular) orbit, gravity provides centripetal force: Fg=FcF_g = F_c.
2) Draw the diagram and define rr carefully
  • Mark centers of masses and the separation distance rr.
  • Direction: gravitational force points toward the attracting mass.

Decision point: If the problem says “altitude hh above Earth,” then r=RE+hr = R_E + h (not just hh).

3) Choose the right equation and solve algebraically

Common “moves”:

  • Replace force with field: g=Fgmg = \frac{F_g}{m}.
  • Replace field with source mass: g=GMr2g = \frac{GM}{r^2}.
  • Set gravity equal to centripetal: GMmr2=mv2r\frac{GMm}{r^2} = \frac{mv^2}{r}.
4) Use superposition when multiple masses act
  • Forces add as vectors: Fnet=Fi\vec F_{net} = \sum \vec F_i.
  • Fields add as vectors: gnet=gi\vec g_{net} = \sum \vec g_i.
5) Check “reasonableness”
  • Inverse-square check: doubling rr should make FgF_g (or gg) become 14\frac{1}{4} as large.
  • Units check: GG makes units work out so FgF_g comes out in newtons.

Key Formulas, Rules & Facts

Constants and symbols you’re expected to know
  • Universal gravitational constant: G=6.67×1011 Nm2/kg2G = 6.67\times 10^{-11}\ \text{N}\cdot\text{m}^2/\text{kg}^2
  • Earth’s surface gravitational field: g9.8 m/s2g \approx 9.8\ \text{m/s}^2 (often use 10 m/s210\ \text{m/s}^2 if told)
Force, field, and weight (most-tested relationships)
RelationshipFormulaWhen to useNotes
Universal gravitational forceFg=Gm1m2r2F_g = \frac{Gm_1m_2}{r^2}Two masses separated by distance rrAlways attractive; direction along line joining centers
Field from a point/spherical massg=GMr2g = \frac{GM}{r^2}Gravitational field magnitude at distance rr from mass MMFor spherically symmetric bodies, treat as if all mass at center (outside)
Force from fieldFg=mg\vec F_g = m\vec gYou know g\vec g at a pointThis is “weight” in any gravitational field
Near-Earth weightFg=mgF_g = mgSmall height changes near EarthAssumes gg constant
Potential energy (near Earth vs universal)
ConceptFormulaWhen to useNotes
Near-Earth gravitational potential energy changeΔUg=mgΔh\Delta U_g = mg\Delta hHeights small relative to Earth radiusChoose zero wherever you like; only changes matter
Universal gravitational potential energyUg=GMmrU_g = -\frac{GMm}{r}Large-scale gravitation (planets/satellites)Negative because gravity is attractive; zero at rr\to\infty
Work-energy linkWg=ΔUgW_g = -\Delta U_gWhen gravity does workGravity does positive work when moving inward (decreasing rr)

Important sign idea: With Ug=GMmrU_g = -\frac{GMm}{r}, decreasing rr makes UgU_g more negative (decreases), meaning gravity releases energy.

Orbits (gravity + circular motion)

These are high-yield because AP loves connecting units.

Orbit quantityFormulaWhen to useNotes
Centripetal forceFc=mv2rF_c = \frac{mv^2}{r}Any uniform circular motionDirection is toward center
Orbital speed (circular orbit)v=GMrv = \sqrt{\frac{GM}{r}}Satellite orbiting mass MM at radius rrComes from Fg=FcF_g = F_c
Orbital periodT=2πrvT = \frac{2\pi r}{v}Convert between period and speedCombine with vv for Kepler-like form
Period-radius-mass relationT=2πr3GMT = 2\pi\sqrt{\frac{r^3}{GM}}Very common orbit questionEquivalent to T2r3T^2 \propto r^3 for fixed MM
Kinetic energy in circular orbitK=12mv2=GMm2rK = \frac{1}{2}mv^2 = \frac{GMm}{2r}Energy in circular orbitUses v2=GMrv^2 = \frac{GM}{r}
Total mechanical energy (circular orbit)E=K+U=GMm2rE = K + U = -\frac{GMm}{2r}Comparing orbits by energyMore negative EE means “more bound”
Scaling relationships (fast comparisons)
  • If rr doubles: Fg14FgF_g \to \frac{1}{4}F_g and g14gg \to \frac{1}{4}g.
  • If one mass doubles: FgF_g doubles.
  • For circular orbit: if rr increases, v1rv \propto \frac{1}{\sqrt{r}} and Tr3/2T \propto r^{3/2}.
Superposition (multiple masses)
  • Force from each source mass MiM_i on a test mass mm:

Fnet=i(GmMiri2 r^i)\vec F_{net} = \sum_i \left(\frac{GmM_i}{r_i^2}\ \hat r_i\right)

  • Field at a point from source masses MiM_i:

gnet=i(GMiri2 r^i)\vec g_{net} = \sum_i \left(\frac{GM_i}{r_i^2}\ \hat r_i\right)

where r^i\hat r_i points toward each mass (direction of the field).


Examples & Applications

Example 1: Compare gravitational force at two distances

A satellite moves from rr to 2r2r from Earth’s center. What happens to gravitational force magnitude?

  • Use inverse-square scaling:

Fg1r2F_g \propto \frac{1}{r^2}

So:

FnewFold=1/(2r)21/r2=14\frac{F_{new}}{F_{old}} = \frac{1/(2r)^2}{1/r^2} = \frac{1}{4}

Insight: You don’t need numbers—just the power law.

Example 2: Gravitational field (weight) at altitude

Find gg at altitude hh above Earth (assume Earth mass MEM_E and radius RER_E).

  • Radius from Earth’s center:

r=RE+hr = R_E + h

  • Field magnitude:

g(h)=GME(RE+h)2g(h) = \frac{GM_E}{(R_E + h)^2}

If they ask “weight,” then Fg=mg(h)F_g = mg(h).

Exam variation: They may ask for the ratio:

g(h)g(0)=GME/(RE+h)2GME/RE2=(RERE+h)2\frac{g(h)}{g(0)} = \frac{GM_E/(R_E+h)^2}{GM_E/R_E^2} = \left(\frac{R_E}{R_E+h}\right)^2

Example 3: Solve for orbital speed

A satellite of mass mm orbits Earth in a circle at radius rr from Earth’s center. Find vv.

  • Set gravity equal to centripetal:

GMEmr2=mv2r\frac{GM_Em}{r^2} = \frac{mv^2}{r}

  • Cancel mm and solve:

v2=GMErv=GMErv^2 = \frac{GM_E}{r} \quad\Rightarrow\quad v = \sqrt{\frac{GM_E}{r}}

Insight: Orbital speed does not depend on the satellite’s mass.

Example 4: Universal potential energy change (big-picture)

A probe moves from r1r_1 to r2r_2 from a planet of mass MM. Find ΔUg\Delta U_g.

  • Use:

Ug=GMmrU_g = -\frac{GMm}{r}

So:

ΔUg=U2U1=GMmr2+GMmr1=GMm(1r11r2)\Delta U_g = U_2 - U_1 = -\frac{GMm}{r_2} + \frac{GMm}{r_1} = GMm\left(\frac{1}{r_1} - \frac{1}{r_2}\right)

Insight: If r2>r1r_2 > r_1 (moving outward), then ΔUg>0\Delta U_g > 0 (you must add energy).


Common Mistakes & Traps

  1. Using hh instead of rr in inverse-square formulas

    • Wrong: g=GMh2g = \frac{GM}{h^2} when altitude is hh.
    • Right: r=RE+hr = R_E + h, so g=GM(RE+h)2g = \frac{GM}{(R_E+h)^2}.
  2. Forgetting gravity is always attractive (sign/direction errors)

    • Students sometimes point Fg\vec F_g away from the planet.
    • Fix: draw arrows toward the attracting mass; use a sign convention consistently.
  3. Mixing up gg and GG

    • GG is universal constant; gg depends on location.
    • Check: g=GMr2g = \frac{GM}{r^2} includes GG.
  4. Treating mgmg as universal

    • Fg=mgF_g = mg is the near-Earth approximation (constant gg).
    • For satellites/planets, use Fg=GMmr2F_g = \frac{GMm}{r^2} or Fg=mg(r)F_g = mg(r) with g(r)=GMr2g(r) = \frac{GM}{r^2}.
  5. Not canceling the orbiting mass mm in orbit equations

    • In GMmr2=mv2r\frac{GMm}{r^2} = \frac{mv^2}{r}, mm cancels.
    • If your final vv depends on satellite mass, you made an algebra mistake.
  6. Confusing potential energy sign (especially with Ug=GMmrU_g = -\frac{GMm}{r})

    • Trap: thinking “higher up means more negative.”
    • Reality: increasing rr makes UgU_g less negative (increases toward 00).
  7. Assuming heavier objects fall faster because gravitational force is bigger

    • Yes, Fg=mgF_g = mg increases with mm, but a=Fm=ga = \frac{F}{m} = g stays the same (ignoring air resistance).
  8. Forgetting superposition is vector-based

    • Two equal masses on opposite sides can cancel fields at a midpoint.
    • Add directions: gnet=g1+g2\vec g_{net} = \vec g_1 + \vec g_2, not just magnitudes.

Memory Aids & Quick Tricks

Trick / mnemonicWhat it helps you rememberWhen to use it
Inverse-square = double distance, quarter effectFgF_g and gg scale as 1r2\frac{1}{r^2}Quick ratio questions
Field is force per massg=Fm\vec g = \frac{\vec F}{m}Converting between field and force
Orbit: set gravity = centripetalGMmr2=mv2r\frac{GMm}{r^2} = \frac{mv^2}{r}Any circular orbit speed/period
Energy in orbit is negativeE=GMm2rE = -\frac{GMm}{2r} (circular)Comparing how ‘bound’ an orbit is
Outside a sphere, treat it like a pointSpherical bodies act like point masses at center (outside)Planets/stars modeled as spheres

Quick Review Checklist

  • You can write and use Newton’s gravitation law: Fg=Gm1m2r2F_g = \frac{Gm_1m_2}{r^2}.
  • You know the definition of field: g=Fgm\vec g = \frac{\vec F_g}{m} and the field of a mass: g=GMr2g = \frac{GM}{r^2}.
  • You correctly use r=RE+hr = R_E + h for altitude problems.
  • You distinguish near-Earth energy ΔUg=mgΔh\Delta U_g = mg\Delta h from universal Ug=GMmrU_g = -\frac{GMm}{r}.
  • You can set up an orbit with Fg=FcF_g = F_c and get v=GMrv = \sqrt{\frac{GM}{r}}.
  • You can get orbital period: T=2πr3GMT = 2\pi\sqrt{\frac{r^3}{GM}}.
  • You remember superposition: gnet=gi\vec g_{net} = \sum \vec g_i with directions.
  • You avoid sign mistakes: gravity points inward; universal UgU_g is negative.

You’ve got the toolkit—now practice picking the right model fast and keeping rr straight.