Model Comparison: Algebra

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Gemini 3 Pro

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What You Need to Know

  • Fluency is key: The "Heart of Algebra" domain makes up approximately one-third of the SAT Math section. Speed and accuracy in manipulating linear equations are critical.

  • Context matters: You must be able to not only solve equations for xx but also interpret the meaning of constants and coefficients (like slope and y-intercept) in real-world word problems.

  • Systems logic: A significant portion involves analyzing systems of equations—not just finding the solution, but identifying how many solutions exist (one, zero, or infinite) based on the structure of the equations.

Linear Equations in One Variable

At the core of algebra is the ability to solve for a single unknown. On the SAT, these questions range from simple arithmetic isolation to complex multi-step problems involving fractions and variables on both sides.

Solving Techniques

To solve a linear equation, apply inverse operations to isolate the variable.

3(2x4)=5x+73(2x - 4) = 5x + 7

  1. Distribute: 6x12=5x+76x - 12 = 5x + 7

  2. Group variables: Subtract 5x5x from both sides. x12=7x - 12 = 7

  3. Isolate: Add 1212 to both sides. x=19x = 19

The Three Types of Solutions

Not all equations yield a single number. You must recognize these special cases immediately:

  1. One Solution: The variables do not cancel out, leaving a distinct value.

    • Example: 2x=10x=52x = 10 \rightarrow x = 5

  2. No Solution (Contradiction): The variable terms cancel out, leaving a false statement. This means the lines are parallel and never intersect.

    • Example: 3x+5=3x+105=103x + 5 = 3x + 10 \rightarrow 5 = 10 (False)

  3. Infinite Solutions (Identity): The variable terms cancel out, leaving a true statement. This means the expressions represent the exact same line.

    • Example: 2(x+3)=2x+66=62(x + 3) = 2x + 6 \rightarrow 6 = 6 (True)

Exam Focus
  • Why it matters: SAT questions often ask you to find the value of a constant kk such that the equation has no solution or infinite solutions.

  • Typical question patterns:

    • "For what value of cc does the equation 3x+7=cx23x + 7 = cx - 2 have no solution?" (Answer: c=3c = 3, because slopes must be equal).

    • Rearranging literal equations: "Solve A=P(1+rt)A = P(1+rt) for tt."

  • Common mistakes: Distributing a negative sign incorrectly (e.g., (3x5)-(3x - 5) becoming 3x5-3x - 5 instead of 3x+5-3x + 5).

Linear Functions and Equations in Two Variables

These questions focus on the relationship between two variables, typically xx and yy, graphed on a coordinate plane.

Key Forms of Linear Equations

Form

Formula

Usage

Slope-Intercept

y=mx+by = mx + b

Easiest for graphing and identifying slope/intercept.

Point-Slope

yy<em>1=m(xx</em>1)y - y<em>1 = m(x - x</em>1)

Best when writing an equation given a slope and a point.

Standard Form

Ax+By=CAx + By = C

Common in word problems dealing with combinations of two items.

Interpreting Slope and Intercept

In word problems, the math concepts map to specific real-world meanings:

  • Slope (mm): The Rate of Change. Look for keywords like "per," "every," or "rate."

    • Formula: m=y<em>2y</em>1x<em>2x</em>1m = \frac{y<em>2 - y</em>1}{x<em>2 - x</em>1}

  • Y-Intercept (bb): The Initial Value or flat fee. The value of yy when x=0x = 0.

Linear Function Components
Parallel and Perpendicular Lines
  • Parallel: Same slope (m<em>1=m</em>2m<em>1 = m</em>2), different y-intercepts.

  • Perpendicular: Negative reciprocal slopes (m<em>1=1m</em>2m<em>1 = -\frac{1}{m</em>2}).

    • Example: If line A has slope 22, a perpendicular line has slope 12-\frac{1}{2}.

Exam Focus
  • Why it matters: Interpretation questions are high-frequency. You may be given a model like C=50+20hC = 50 + 20h and asked "What is the best interpretation of the number 20?"

  • Typical question patterns:

    • Converting Standard Form (3x+4y=123x + 4y = 12) to Slope-Intercept Form to identify the slope (m=34m = -\frac{3}{4}).

    • Calculating the slope from a table of values.

  • Common mistakes: Confusing the xx and yy values in the slope formula (putting run/rise{run} / {rise} instead of rise/run{rise} / {run}).

Systems of Linear Equations

A system consists of two or more linear equations. The solution is the point (x,y)(x, y) where the lines intersect.

Solving Methods
  1. Substitution: Isolate one variable in the first equation and plug it into the second.

    • Best when one variable has a coefficient of 1 (e.g., x=2y4x = 2y - 4).

  2. Elimination (Combination): Add or subtract the equations to eliminate a variable.

    • Best when variables are aligned and coefficients are multiples (e.g., 3x3x and 3x-3x).

Number of Solutions in Systems

Just like single-variable equations, systems have three possibilities based on the geometric relationship of the lines:

Number of Solutions

Geometric Meaning

Algebraic Condition

One Solution

Lines intersect at one point

Different Slopes (m<em>1m</em>2m<em>1 \neq m</em>2)

No Solution

Parallel lines

Same Slope, Different Intercepts (m<em>1=m</em>2,b<em>1b</em>2m<em>1 = m</em>2, b<em>1 \neq b</em>2)

Infinite Solutions

Identical lines

Same Slope, Same Intercept (m<em>1=m</em>2,b<em>1=b</em>2m<em>1 = m</em>2, b<em>1 = b</em>2)

Exam Focus
  • Why it matters: Recognizing the condition for "no solution" without fully solving the system saves valuable time.

  • Typical question patterns:

    • "If the system has no solution, what is the value of kk?"

    • Word problems involving two different items (e.g., "Adult tickets cost 1010, child tickets cost 55, total sales were 500500…").

  • Common mistakes: Forgetting to multiply the constant term on the right side of the equals sign when scaling an equation for elimination.

Linear Inequalities

Inequalities work similarly to equations but represent regions of possible solutions rather than specific points.

Solving and Graphing
  • The Golden Rule: When you multiply or divide an inequality by a negative number, you must flip the inequality sign.

    • -2x > 10 \rightarrow x < -5

  • Graphing Lines:

    • Strict inequalities (<, >) use dashed lines.

    • Inclusive inequalities (,\leq, \geq) use solid lines.

  • Shading:

    • y > … or yy \geq … : Shade the region above the line.

    • y < … or yy \leq … : Shade the region below the line.

System of Inequalities
Systems of Inequalities

The solution to a system of inequalities is the overlapping shaded region where all inequalities are true simultaneously. Points on a solid boundary line are solutions; points on a dashed boundary line are not.

Exam Focus
  • Why it matters: These questions test visual literacy—can you match an algebraic statement to a graph?

  • Typical question patterns:

    • "Which graph represents the system y2x+1y \ge 2x + 1 and y < -x?"

    • "Is point (2,3)(2, 3) a solution to the system?" (Test by plugging in values).

  • Common mistakes: Shading the wrong side of a vertical line (x > 3 is to the right, x < 3 is to the left).

Quick Review Checklist

  • Can you rewrite 3x+4y=123x + 4y = 12 into y=mx+by = mx + b form correctly?

  • Do you know the specific condition required for a system to have zero solutions?

  • Can you calculate the slope given two points, (x<em>1,y</em>1)(x<em>1, y</em>1) and (x<em>2,y</em>2)(x<em>2, y</em>2)?

  • Do you remember to flip the inequality sign when dividing by a negative number?

  • Can you interpret what the y-intercept represents in a real-world word problem?

  • Can you identify perpendicular slopes (e.g., 22 and 0.5-0.5)?

Final Exam Pitfalls

  1. The "No Solution" Trap

    • Mistake: Trying to solve for xx and yy when the question asks for a constant kk that creates no solution.

    • Fix: Immediately set the slopes equal to each other (m<em>1=m</em>2m<em>1 = m</em>2) and solve for kk. Do not solve for xx.

  2. Units Mismatch

    • Mistake: Using minutes in an equation designed for hours.

    • Fix: Always check if the rate (e.g., miles per hour) matches the time variable given (e.g., 30 minutes). Convert 3030 minutes to 0.50.5 hours before plugging it in.

  3. Sign Errors in Elimination

    • Mistake: Subtracting the entire second equation but forgetting to distribute the negative sign to the constant term.

    • Fix: Instead of subtracting, multiply the second equation by 1-1 and add the two equations. Addition is less prone to error than subtraction.

  4. Inequality Boundary Points

    • Mistake: Assuming a point on the line is a solution for a strict inequality (< or >).

    • Fix: If the line is dashed (< or >), points exactly on the line are not solutions. Only points in the shaded region count.


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GPT 5.2 Pro

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What You Need to Know

  • SAT Math Algebra (per College Board’s SAT Math content domains) focuses on linear equations, linear inequalities, linear functions, and systems—often in real-world contexts like rates, costs, and comparisons.

  • You must fluently move between forms of a line (especially y=mx+by = mx + b and Ax+By=CAx + By = C), interpret mm (rate of change) and bb (starting value), and solve for unknowns accurately.

  • Many questions test not just solving, but modeling: setting up an equation/inequality from words, tables, or graphs, then interpreting the solution.

  • SAT Math questions appear as multiple-choice and student-produced response; algebra skills are among the most frequently used across the test.

Linear equations in 1 variable

Core idea

A linear equation in one variable is an equation that can be written as ax+b=cax + b = c where a,b,ca, b, c are constants and a0a \neq 0. Solving means finding the value of xx that makes the equation true.

Key skills
  • Inverse operations: undo addition/subtraction, then multiplication/division.

  • Distribute and combine like terms correctly:

    • a(b+c)=ab+aca(b + c) = ab + ac

  • Handle fractions/decimals strategically:

    • Multiply both sides by the least common denominator to clear fractions.

Worked example 1 (distribution)

Solve 3(x2)=123(x - 2) = 12.

  1. Distribute: 3x6=123x - 6 = 12

  2. Add 66 to both sides: 3x=183x = 18

  3. Divide by 33: x=6x = 6

Worked example 2 (fractions)

Solve x3+12=2\frac{x}{3} + \frac{1}{2} = 2.

  1. Multiply both sides by 66 (LCD):

    • 6x3+612=626 \cdot \frac{x}{3} + 6 \cdot \frac{1}{2} = 6 \cdot 2

  2. Simplify: 2x+3=122x + 3 = 12

  3. Subtract 33: 2x=92x = 9

  4. Divide by 22: x=92x = \frac{9}{2}

Exam Focus
  • Why it matters: One-variable linear equations are a foundation—SAT often embeds them in word problems and multi-step algebra.

  • Typical question patterns:

    • Solve an equation with parentheses and like terms (e.g., a(x+b)=ca(x+b)=c).

    • Solve for a variable in a formula (literal equations), e.g., isolate xx.

    • Word problem leading to ax+b=cax+b=c (tax, discounts, fees).

  • Common mistakes:

    • Distributing incorrectly (forgetting to multiply every term inside parentheses).

    • Sign errors when moving terms (especially subtracting negatives).

    • Clearing fractions inconsistently (not multiplying every term by the LCD).

Linear equations in 2 variables

Core idea

A linear equation in two variables represents a line in the coordinate plane. Common forms:

Form

Equation

What it highlights

Slope-intercept

y=mx+by = mx + b

Slope mm and intercept bb

Standard

Ax+By=CAx + By = C

Integer coefficients; useful for elimination

Point-slope

yy<em>1=m(xx</em>1)y - y<em>1 = m(x - x</em>1)

Line through a point with slope mm

Key skills
  • Convert between forms (often from Ax+By=CAx + By = C to y=mx+by = mx + b).

  • Find intercepts quickly:

    • xx-intercept: set y=0y = 0.

    • yy-intercept: set x=0x = 0.

  • Build an equation from information:

    • From slope and a point.

    • From two points.

Worked example 1 (standard to slope-intercept)

Convert 3x+2y=103x + 2y = 10 to slope-intercept form.

  1. Subtract 3x3x: 2y=3x+102y = -3x + 10

  2. Divide by 22: y=32x+5y = -\frac{3}{2}x + 5
    So m=32m = -\frac{3}{2} and b=5b = 5.

Worked example 2 (equation through two points)

Find the line through (2,1)(2, 1) and (6,9)(6, 9).

  1. Slope: m=9162=84=2m = \frac{9-1}{6-2} = \frac{8}{4} = 2

  2. Use y=mx+by = mx + b with (2,1)(2,1):

    • 1=2(2)+b1 = 2(2) + b

    • 1=4+bb=31 = 4 + b \Rightarrow b = -3

  3. Equation: y=2x3y = 2x - 3

Exam Focus
  • Why it matters: Lines are central to SAT algebra modeling—equations represent relationships (cost vs. quantity, distance vs. time).

  • Typical question patterns:

    • Convert forms and identify mm and bb.

    • Use intercepts to interpret a context (starting fee, break-even point).

    • Write the equation given two points or a table pattern.

  • Common mistakes:

    • Mixing up slope formula order; remember consistent subtraction: y<em>2y</em>1x<em>2x</em>1\frac{y<em>2-y</em>1}{x<em>2-x</em>1}.

    • Treating AA or CC in Ax+By=CAx+By=C as slope (it isn’t unless rearranged).

    • Arithmetic slips when isolating yy (especially dividing every term by BB).

Linear functions

Core idea

A linear function is a function whose output changes at a constant rate. It can be written as:

  • f(x)=mx+bf(x) = mx + b

  • Equivalent to y=mx+by = mx + b if y=f(x)y = f(x)

Interpreting parameters
  • mm = rate of change (rise/run). In contexts, it’s often a unit rate (e.g., dollars per hour).

  • bb = initial value (value when x=0x=0).

Common representations and what SAT asks
  • Equation: identify mm and bb.

  • Table: compute constant change in yy per change in xx.

  • Graph: read slope from two points.

  • Words: translate to mx+bmx+b.

Worked example 1 (table to function)

A table shows points (0,7)(0, 7) and (4,15)(4, 15) on a linear function.

  1. Slope: m=15740=84=2m = \frac{15-7}{4-0} = \frac{8}{4} = 2

  2. Since f(0)=7f(0)=7, b=7b=7.

  3. Function: f(x)=2x+7f(x) = 2x + 7

Worked example 2 (real-world model)

A gym charges a signup fee of $30\$30 plus $15\$15 per month. Let mm be months and CC be total cost.

  • Model: C=15m+30C = 15m + 30

  • Interpretation: 1515 is monthly rate; 3030 is starting cost.

Exam Focus
  • Why it matters: SAT frequently tests function interpretation—linking slope/intercept to meaning is a high-value skill.

  • Typical question patterns:

    • Given a context, identify what mm and bb represent.

    • Compare two linear functions to decide which grows faster.

    • Evaluate: compute f(a)f(a) or solve f(x)=kf(x)=k.

  • Common mistakes:

    • Confusing f(0)f(0) with f(1)f(1)—only x=0x=0 gives the intercept.

    • Using the wrong “change in xx” when finding slope from a table.

    • Treating a non-constant rate table as linear (check that slope is consistent).

Systems of 2 linear equations in 2 variables

Core idea

A system of linear equations is two linear equations with the same variables, such as:
\begin{cases}
ax + by = c \
px + qy = r
\end{cases}
A solution (x,y)(x, y) must satisfy both equations. Graphically, it’s the intersection of two lines.

Types of solutions
  • One solution: lines intersect once.

  • No solution: lines are parallel (same slope, different intercept).

  • Infinitely many solutions: lines are the same (equivalent equations).

Methods
  1. Substitution: solve one equation for a variable, plug into the other.

  2. Elimination: add/subtract equations to eliminate a variable (often easiest with standard form).

Worked example (elimination)

Solve:
\begin{cases}
2x + y = 11 \
2x - y = 1
\end{cases}

  1. Add equations to eliminate yy:

    • (2x+y)+(2xy)=11+1(2x + y) + (2x - y) = 11 + 1

    • 4x=124x = 12

  2. Solve: x=3x = 3

  3. Substitute into 2x+y=112x + y = 11:

    • 2(3)+y=112(3) + y = 11

    • 6+y=11y=56 + y = 11 \Rightarrow y = 5
      Solution: (3,5)(3, 5).

SAT modeling note

Systems often represent constraints (e.g., tickets sold of two types). Your job is to define variables clearly, then translate sentences to equations.

Exam Focus
  • Why it matters: Systems test multi-step reasoning and modeling; they appear in both pure algebra and word problems.

  • Typical question patterns:

    • Solve for (x,y)(x,y) using elimination/substitution.

    • Determine number of solutions by comparing slopes/intercepts.

    • Word problem: two unknown quantities with two conditions.

  • Common mistakes:

    • Eliminating incorrectly (forgetting to multiply an entire equation).

    • Algebra slip after substitution (especially distributing negatives).

    • Misinterpreting “no solution” vs “infinite solutions” (check proportionality of coefficients and constants).

Linear inequalities in 1 or 2 variables

Core idea

A linear inequality uses <, \le, >, \ge and describes a set of solutions.

One-variable inequalities

Solve like equations, with one critical rule:

  • If you multiply or divide both sides by a negative number, flip the inequality sign.

Worked example 1 (flip the sign)

Solve 2x+513-2x + 5 \ge 13.

  1. Subtract 55: 2x8-2x \ge 8

  2. Divide by 2-2 and flip: x4x \le -4

Compound inequalities

Example: 2 \le 3x + 1 < 10

  1. Subtract 11 from all three parts: 1 \le 3x < 9

  2. Divide by 33: \frac{1}{3} \le x < 3

Two-variable inequalities

A linear inequality in two variables describes a half-plane:

  • Boundary line from the related equation (replace inequality with ==).

  • Solid line for \le or \ge; dashed line for < or >.

  • Use a test point (often (0,0)(0,0) if allowed) to decide which side to shade.

Worked example 2 (test point)

Graph/identify the solution region for y > -x + 2.

  1. Boundary: y=x+2y = -x + 2 (dashed because >).

  2. Test point (0,0)(0,0):

    • Check: 0 > -(0) + 2 \Rightarrow 0 > 2 (false)

  3. Shade the side not containing (0,0)(0,0) (above the line in this case).

Exam Focus
  • Why it matters: Inequalities are common in constraint and “range of values” problems—especially when interpreting conditions.

  • Typical question patterns:

    • Solve and express the solution set (including compound inequalities).

    • Identify which value satisfies an inequality (plug-and-check options).

    • Interpret a graphed half-plane or write an inequality from a graph.

  • Common mistakes:

    • Forgetting to flip the sign when dividing/multiplying by a negative.

    • Using solid vs dashed boundary incorrectly.

    • Testing the wrong point or plugging into the boundary equation instead of the inequality.

Quick Review Checklist
  • Can you solve ax+b=cax+b=c equations accurately, including with parentheses and fractions?

  • Can you rearrange Ax+By=CAx+By=C into y=mx+by=mx+b and identify mm and bb?

  • Can you find the equation of a line from two points using m=y<em>2y</em>1x<em>2x</em>1m = \frac{y<em>2-y</em>1}{x<em>2-x</em>1}?

  • Can you interpret mm as a rate of change and bb as an initial value in context?

  • Can you solve a system using elimination and check the solution in both equations?

  • Can you decide whether a system has 0, 1, or infinitely many solutions?

  • Can you solve inequalities and remember when to flip the inequality sign?

  • Can you determine the correct shaded region for ymx+by \gtrless mx+b using a test point?

Final Exam Pitfalls
  1. Sign errors when distributing or moving terms — Write one step per line and re-check negatives (especially (x3)-(x-3)).

  2. Forgetting to flip an inequality — Any time you divide or multiply by a negative (like 2-2), reverse < to > (and \le to \ge).

  3. Mixing up slope and intercept — In y=mx+by=mx+b, mm is the coefficient of xx and bb is the value when x=0x=0.

  4. Elimination mistakes in systems — If you multiply an equation by a number, multiply every term (including constants) before adding/subtracting.

  5. Misreading what a solution means — For a system, a solution is an ordered pair (x,y)(x,y); for an inequality, the solution is a set/range, not a single value unless specified.


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Claude Opus 4.6

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Claude Opus 4.6

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What You Need to Know

  • Algebra accounts for approximately 35% of the SAT Math section (roughly 13–15 questions out of 44), making it the single highest-weighted domain on the entire test.

  • Every algebra question ultimately tests your ability to set up, manipulate, or interpret linear relationships — whether as equations, inequalities, functions, or systems.

  • The SAT rewards strategic reasoning over brute-force calculation: look for structure, use substitution or elimination efficiently, and always check whether the question asks for the variable, an expression, or a real-world interpretation.

  • Comfort with slope-intercept form, point-slope form, and standard form is essential — you need to convert between them fluently.


Linear Equations in 1 Variable

A linear equation in one variable is an equation that can be simplified to the form ax+b=0ax + b = 0, where a0a \neq 0. Solving means isolating the variable through inverse operations.

Core Techniques
  1. Distribute any parentheses.

  2. Combine like terms on each side.

  3. Move variable terms to one side and constants to the other.

  4. Divide by the coefficient.

Worked Example

Solve: 3(2x5)+4=2x+73(2x - 5) + 4 = 2x + 7

Step

Work

Distribute

6x15+4=2x+76x - 15 + 4 = 2x + 7

Combine like terms

6x11=2x+76x - 11 = 2x + 7

Subtract 2x2x

4x11=74x - 11 = 7

Add 1111

4x=184x = 18

Divide by 44

x=184=92x = \frac{18}{4} = \frac{9}{2}

Special Cases

Outcome

Meaning

Example

One solution

Unique value of xx

2x+1=5x=22x + 1 = 5 \Rightarrow x = 2

No solution

Variable cancels, false statement

x+3=x+73=7x + 3 = x + 7 \Rightarrow 3 = 7

Infinitely many solutions

Variable cancels, true statement

2(x+1)=2x+22=22(x+1) = 2x + 2 \Rightarrow 2 = 2

The SAT frequently asks you to find a value of a constant that makes an equation have no solution or infinitely many solutions.

Exam Focus
  • Why it matters: These questions appear in both the no-calculator and calculator modules and test foundational algebraic fluency.

  • Typical question patterns:

    • Solve for xx (often the answer is a fraction)

    • "For what value of kk does the equation have no solution?"

    • "What is the value of 3x23x - 2 given the equation?" (solve for the expression, not xx alone)

  • Common mistakes:

    • Forgetting to distribute a negative sign across parentheses

    • Answering with the value of xx when the question asks for an expression like 2x+12x + 1

    • Dividing incorrectly when the coefficient is negative


Linear Equations in 2 Variables

A linear equation in two variables takes the general form ax+by=cax + by = c and represents a straight line on the coordinate plane. Every point (x,y)(x, y) on the line is a solution.

Key Forms

Form

Equation

Best Used For

Slope-intercept

y=mx+by = mx + b

Reading slope and y-intercept directly

Standard

ax+by=cax + by = c

Finding intercepts, working with systems

Point-slope

yy<em>1=m(xx</em>1)y - y<em>1 = m(x - x</em>1)

Writing an equation from a point and slope

Slope

The slope measures the rate of change between two points (x<em>1,y</em>1)(x<em>1, y</em>1) and (x<em>2,y</em>2)(x<em>2, y</em>2):

m=y<em>2y</em>1x<em>2x</em>1m = \frac{y<em>2 - y</em>1}{x<em>2 - x</em>1}

Memory aid: "Rise over run" — vertical change divided by horizontal change.

Intercepts
  • y-intercept: Set x=0x = 0 and solve for yy.

  • x-intercept: Set y=0y = 0 and solve for xx.

Parallel vs. Perpendicular Lines

Relationship

Slope Condition

Parallel

Same slope: m<em>1=m</em>2m<em>1 = m</em>2

Perpendicular

Negative reciprocal: m<em>1m</em>2=1m<em>1 \cdot m</em>2 = -1

Exam Focus
  • Why it matters: Understanding linear equations in two variables is the foundation for graphing, systems, and word problems throughout the algebra domain.

  • Typical question patterns:

    • Identify the slope or y-intercept from an equation or graph

    • Write the equation of a line given two points or a point and slope

    • Determine if two lines are parallel or perpendicular

  • Common mistakes:

    • Mixing up xx and yy when calculating slope (subtracting in different orders)

    • Forgetting to convert to slope-intercept form before reading the slope

    • Confusing "perpendicular" with "negative slope" rather than "negative reciprocal"


Linear Functions

A linear function is a function of the form f(x)=mx+bf(x) = mx + b whose graph is a straight line. The SAT tests your ability to interpret these functions in context.

Interpreting in Context

When a word problem says "A repair company charges a \$50 service fee plus \$30 per hour," the function is:

f(h)=30h+50f(h) = 30h + 50

  • Slope (3030): the rate — cost per hour

  • y-intercept (5050): the initial value — the flat service fee

Function Notation
  • f(3)f(3) means substitute x=3x = 3 into the function

  • If f(a)=0f(a) = 0, then aa is the x-intercept (also called the zero of the function)

Worked Example

A gym membership costs \$25 per month after a \$60 sign-up fee. Write a function for total cost CC after mm months and find the cost after 8 months.

C(m)=25m+60C(m) = 25m + 60

C(8)=25(8)+60=200+60=260C(8) = 25(8) + 60 = 200 + 60 = 260

The total cost after 8 months is $260\$260.

Exam Focus
  • Why it matters: The SAT emphasizes real-world interpretation of slope and intercept — expect at least 2–3 questions that ask "what does the number bb represent in context?"

  • Typical question patterns:

    • "Which of the following represents the meaning of the slope?"

    • Evaluate f(k)f(k) for a given value

    • Determine the zero of the function in context

  • Common mistakes:

    • Confusing slope with y-intercept when interpreting word problems

    • Misidentifying which quantity is independent (xx) vs. dependent (yy)

    • Giving the value of f(x)f(x) when asked for xx when f(x)=kf(x) = k


Systems of 2 Linear Equations in 2 Variables

A system of two linear equations consists of two equations with two unknowns. The solution is the point (x,y)(x, y) where the two lines intersect.

Solution Methods

Method

When to Use

Substitution

One variable is already isolated or easy to isolate

Elimination

Coefficients can be matched by simple multiplication

Worked Example (Elimination)

Solve: 2x+3y=122x + 3y = 12 and 4x3y=64x - 3y = 6

Add the two equations: 6x=186x = 18, so x=3x = 3.

Substitute back: 2(3)+3y=123y=6y=22(3) + 3y = 12 \Rightarrow 3y = 6 \Rightarrow y = 2.

Solution: (3,2)(3, 2).

Number of Solutions

Condition

Graph

Solutions

Different slopes

Lines intersect

Exactly one

Same slope, different intercept

Parallel lines

None

Same slope, same intercept

Same line

Infinitely many

Exam Focus
  • Why it matters: Systems questions appear regularly and often in word-problem form (e.g., ticket prices, mixture problems).

  • Typical question patterns:

    • Solve and find x+yx + y or another combined expression

    • "How many solutions does the system have?"

    • Set up a system from a word problem and solve

  • Common mistakes:

    • Forgetting to multiply both sides of an equation when using elimination

    • Solving for one variable but forgetting to find the other (or the expression asked for)

    • Misinterpreting "no solution" — this means parallel lines, not x=0x = 0


Linear Inequalities in 1 or 2 Variables

A linear inequality uses <, >, \leq, or \geq instead of ==. The solution is a range of values (1 variable) or a region of the coordinate plane (2 variables).

One-Variable Inequalities

Solve just like equations with one critical rule:

When you multiply or divide both sides by a negative number, flip the inequality sign.

Example: -3x + 6 > 12

-3x > 6

x < -2 (sign flipped)

Two-Variable Inequalities

The inequality y > mx + b represents the region above the line y=mx+by = mx + b.

Inequality

Line Style

Shaded Region

y > mx + b

Dashed

Above

ymx+by \geq mx + b

Solid

Above

y < mx + b

Dashed

Below

ymx+by \leq mx + b

Solid

Below

Systems of Inequalities

The solution to a system of inequalities is the overlapping shaded region of all inequalities.

Graph of a system of two linear inequalities showing the overlapping shaded region
Exam Focus
  • Why it matters: Inequality questions test both algebraic manipulation and graphical reasoning, and they appear in both pure math and word-problem contexts.

  • Typical question patterns:

    • Solve a one-variable inequality and identify the solution on a number line

    • Identify which graph represents a given inequality

    • Determine whether a point satisfies a system of inequalities

  • Common mistakes:

    • Forgetting to flip the inequality sign when dividing by a negative

    • Confusing dashed (strict inequality) with solid (inclusive inequality) lines

    • Shading the wrong side of the boundary line


Quick Review Checklist

  • Can you solve a linear equation in one variable, including ones with no solution or infinitely many solutions?

  • Do you know how to convert between slope-intercept, standard, and point-slope forms?

  • Can you calculate slope from two points using m=y<em>2y</em>1x<em>2x</em>1m = \frac{y<em>2 - y</em>1}{x<em>2 - x</em>1}?

  • Can you interpret slope and y-intercept in a real-world context?

  • Do you know when two lines are parallel vs. perpendicular?

  • Can you solve a system of equations using both substitution and elimination?

  • Can you determine the number of solutions a system has without fully solving it?

  • Do you remember to flip the inequality sign when multiplying or dividing by a negative?

  • Can you graph a linear inequality and identify the correct shaded region?

  • Can you set up equations or systems from word problems?


Final Exam Pitfalls

  1. Reading the question too quickly — The SAT often asks for 2x+12x + 1 instead of xx. Always re-read what the question is asking for before selecting your answer.

  2. Forgetting to flip the inequality sign — This is the single most common algebra error. Whenever you multiply or divide by a negative, reverse the direction of the inequality.

  3. Confusing "no solution" with x=0x = 0 — "No solution" means no value of xx works (the equation is a contradiction). It does not mean the answer is zero.

  4. Misidentifying slope vs. y-intercept in word problems — The slope is always the rate (per unit), and the y-intercept is the starting or fixed value. Read carefully to distinguish them.

  5. Arithmetic errors in elimination — When multiplying an equation to align coefficients, multiply every single term, including the constant on the right side.

  6. Ignoring the domain in context problems — If xx represents months or items sold, negative and non-integer values may not make sense. Always check whether your answer is reasonable in context.