4.5 Activation and Deactivation
4.5 Activation and Deactivation
- Make sure you can draw a mechanism for the sulfonation of benzene on a separate piece of paper.
- There will be three steps, the first of which is the transfer of protons.
- Don't forget to draw the resonance structures of the intermediate sigma complexample if you want to draw the mechanism.
- The process will be the same as when you drew it.
- The SO H group will be removed, H+ will come on the ring, and SO will leave the ring.
- Make sure your mechanism involves an intermediate sigma complex.
- In order to make a reaction happen, we introduced a Lewis acid into the mixture, which created a better electrophile.
- We will consider the effect that a substituent will have on the reactivity of the ring when we answer this question.
- Benzene has no substituents.
- An OH group is one of the substituents in the aromatic ring.
- An OH group has an effect on the electron density of the aromatic ring.
- Let's start with something.
- In the first semester, the relative electronegativity of the atoms can be compared.
- The OH group is connected to the ring by the C--O bond.
- The oxygen atom is leaving the ring.
- We need to think about resonance.
- There is a negative charge spread throughout the ring.
- There is a partial negative charge spread throughout the ring.
- We have a competition.
- There are exceptions.
- We will soon see one of these exceptions, but in general resonance wins.
- Let's apply this rule to our case.
- Experiments show that phenol is more nucleophilic than benzene.
- The ring is said to be being activated by the OH group.
- An effect called hyperconjugation is what causes alkyl groups to be electron donating.
- The nitro group is an excellent example.