Chapter 13: Membrane Channels and Pumps

Chapter 13: Membrane Channels and Pumps

  • Two classes of transmembrane proteins--pumps and channels-- can be used to circumvent the impermeability of the lipid bilayer.
  • Some of the structural and functional features of pro teins are described in this chapter.
    • The authors first differentiate between active transport and passive transport and then discuss how to quantitate the free energy stored in concentration gradients.
    • There are three types of active transport systems: the P-type ATPases, the ABC pumps, and the secondary transporters.
    • There are many structural and mechanistic features in the Na+-K+ and sarcoplasmic reticulum Ca2+-ATPases.
    • The family of ABC pumps that have recently been identified include the multidrug resistance protein and the cystic fibrosis transmembrane conductance regulator.
    • The mechanism of secondary transporters is examined in the discussion of active transport.
  • In addition to active transport, ion channels can be used.
    • The key properties of all channels are discussed by the authors.
    • Researchers can measure the activity of a single ion channel using the patch-clamp technique.
    • Two types of ion channels important in the propagation of nerve impulses are examined in detail.
    • The chapter ends with a discussion of gap junctions, which act as cell-to-cell channels and allow all polar molecules with less than 1 kDa to pass through.
  • You should be able to complete the objectives when you master this chapter.

  • There are two factors that determine whether a molecule crosses a membrane.

  • The rates of transport through channels are different from the rates of active transport.
  • List the sequence of steps in the action potential.
  • The structure, ion selectivity, and inactivation mechanism of the potassium channel are compared.
  • The structure of the channel should be compared to its rate of transport.
  • There are examples ofmol ecules that can pass through gap junctions.
  • The side of the mem brane where the various processes involved in the transport of Na+ and K+ will take place is determined by the orientation of the Na+-K+ pump.
  • The existence of four different states of the Ca2+-ATPase is the basis for the proposed model.
  • The exchanger is used for calcium and sodium transport.
  • If you want to describe the characteristics in the right column, you have to write them down.
  • List the events in the transmission of nerve impulses.
  • The action potential should be placed in their correct sequence.
  • The corre sponding properties are listed in the right column.
  • Active transport must be used since the transport is unfavorable in the direction indicated by the sign of DG.
  • There is a net efflux of one positively charged ion if three Na+ ion are transported out for every two K+ ion.
  • The answer is yes.
    • While prokaryotic ABCs are often multisubunit, eukaryotic ABCs usually have the same domain on the same polypeptide.
  • The answer is incorrect.
    • The exchanger transports the cations in the opposite direction.
  • A column with covalently attached cobratoxin can be used in the purification of the acetylcholine receptor from a mixture of macromolecules in the postsynaptic membrane that has been solubilized.
  • Correct answer (c) is incorrect.
    • The diameter of the channel is not uniform.
  • The concentrations of Na+ and K+ are 150 and 140 mM, respectively, in dog skeletal muscle.
  • The temperature is 25oC and the potential is -60 mV.
  • A molecule is transported from one side to the other.
  • The Na+-K+ATPase is one of the pumps in the cells.
    • One such pump is the H+-K+ ATPase, in which a hydrogen ion is removed from the cytoplasm in exchange for a potassium ion.
    • Explain why the Na+-K+ ATPase can contribute to the potential of the cell but the H+-K+ATPase can't.
  • In experiments to investigate the mechanism of transport of two substances, X and Y, across cell membranes, cells were incubated in media containing various concentrations of X and Y, and the initial rate of transport of each of the substances into the cell was determined.
    • It is helpful to refer to the discussion of the enzymes in the text.
  • If you want to see if the Na+-K+ ATPase reaction involves a stable enzyme-phosphate intermediate, you can design an experiment using the labeled ATP with 32P in the g position.
  • The rising phase of the action potential and the falling phase are caused by certain events.
    • If the ion flow occurs against concentration gradients or both, specify it.
  • There is a narrow region of the sodium channel.
    • Val is replaced by a mu tant protein.
  • 9 x 298 x ln 5 is a negative number.
  • The total is 1.99 x 298 x ln.
  • The entry of a positively charged ion is aided by the membrane potential.
    • The free energy change will be less favorable if the calculation is repeated for a negatively charged molecule.
  • The sum of the two will be the total free-energy change.

9 x 298 x ln + 23 x 062

  • When Na+ is taken out of the cell, work must be done against both a concentration and electrical gradient.
  • The calculation for the K+ ion is done now.

9 x 298 x ln + 23 x 062

  • The concentration is being transported against an electrical gradient.
    • The sign for the electrical term in the equation is negative.
  • To get the total energy expenditure, we have to account for the transport of Na+ and K+.
  • The energy furnished by the hydrolysis of a single ATP is sufficient.
  • A molecule is transported from one side to the other.
  • The molecule will move down its concentration gradient if the concentration on side 1 is higher than the concentration on side 2.
  • The rate of a chemical process is always the same as the rate constant.
    • The rate of transport will be greater in (b) than in (a).
  • The difference between the two systems is their ex change of ion.
    • The inside of the cell is more negative for each pump cycle due to the fact that there are three Na+ ion and two K+ ion taken up.
    • The H+-K+ ATPase extrudes one H+ ion for each K+ taken up, so its operation is neutral.
  • Resistance to one drug can make cells less sensi tive to other drugs.
    • There is a correlation between the expression and activity of a 170 kDa protein called Multidrug ResistanceProtein (MDR) and the development of multidrug resistance.
  • The drugs are pumped out of cells before they can exert their effects.
  • If a carrier is involved in the transport of substance X, the curve for X shows saturation.
    • The curve for Y shows no saturation, which is consistent with the idea that substance Y diffuses without a carrier.
    • Such behavior is shown by substances that can enter cells without a carrier.
  • In the first half-reaction, the first product of the reaction,ADP, is created when the two main components of the reaction, ATP and unmodified, interact in the presence of Na+ and Mg2+.
    • In the second half-reaction, the phosphorylated enzyme is hydrolyzed by water in the presence of K+.
  • An overall reaction would be suggested by the following experiment.
  • Incubate a fragmented preparation with K+ ion to hydrolyze anyphosphate that might be bound to the enzyme.
    • After washing the preparation to remove K+, transfer it to a medium containing g-labeled ATP, Na+, and Mg2+.
  • After a suitable period of time, wash the preparation.
    • You can detect the presence of labeled phosphate with scintillation counting.
    • The presence of radioactivity in the fraction would suggest that a stable intermediate had been formed.
    • There is a covalent aspartylphosphate derivative at the active site.
  • Nerve cells have a higher concentration of K+ inside than out side and a higher concentration of Na+ outside than inside.
    • The inside of the cell is negative with respect to the outside.
  • Only a small number of Na+ and K+ ion enter and leave the cell for each action potential that is generated in an axon.
    • In a poisoned nerve cell, many tens of thousands of impulses may be conducted before ionic equilibrium is achieved.
    • In the long run, the active transport of Na+ and K+ is necessary, but not in the short run.
  • The Na+ conductance would have been decreased if a Mutant pro tein was found in the narrow region of the sodium channel.
    • The charge between Na+ ion and carboxylate anions is important in drawing Na+ into the channel.
    • The un charged side chain of Val won't attract Na+ ion.
  • There are no charged groups in the side chain of Val that would show a sensitivity to pH.
  • The positively charged guanido group is likely to interact with the negatively charged group in the sodium channel.
  • The action potential is created by the flow of sodium from the outside of the cell to the inside.
    • The magnitude of the action potential would be reduced due to the reduced amount of sodium conductance in the Mutant.
  • Form reconstituted vesicles with each oriented in the Membrane so that its face is towards the inside of the vesicle.
    • The hydrogen ion will be created by bacteriorhodopsin when the vesicles areilluminated.
    • The entry of Lactose will be driven by the hydrogen ion gradient.
  • The electrochemical gradient for Na+ influx is larger than that for K+efflux.
    • Na+ moves from the positive to the negative side of the membrane, whereas K+ moves from the negative to the positive side, which favors Na+ influx.
  • There is a cations binding substance at the entrance of the potassium channel.
    • The energy required to dehydrate Na+ and smaller cations is too large and is not compensated by favorable polar interactions that occur in the case of K+.
  • The ball and chain model of channel inactivation is supported by two pieces of experimental evidence.
    • The Na+ or K+ channel can be trimmed with trypsin if it is treated on the cytoplasmic side.
    • There are two things that show that the N-terminal splice variant of the potassium channel has changed.
    • A deletion of 42 amino acids at the N-terminus causes the channel to open but not inactivate.
    • Adding a syntheticpeptide corresponding to the deleted amino acids restores inactivation to the channel.

  • It is 105 x (5 x 10-2)4 for four ligands.
  • The fractions of open chan nels are 10-5, 2 x 10-4, 3.98 x 10-3, 7.41 x 10-2, and 0.615.
  • The three molecules all contain highly reactive phosphoryl groups that readily react with the active-site serine of acetylcholinesterase to form a stable derivative.
    • Respiratory paralysis can be caused by synaptic transmission being impossible without active acetylcholinesterase.
  • The log (240) x 1.36 is the free-energy change during the binding of the first acetylcholine.
  • The closed/open ratio will be the same effect as the binding of the ligand.
    • The channel is not perfect.
    • The two chains are not in the same place.
    • The presence of desensitized states in addition to the open and closed ones indicates that a more complex model is required.
  • The voltage needed to open half the channels is -22 mV.
  • The table below shows the information that was given.

  • The slope is 173 4.
  • Substituting, we get 4.5 x 23 kcal V-1 mol-1 x 0.05 V.
  • The channels do not provide any energy or allow any passive transport of ion.
    • In the opposite direction, potassium ion flow.
    • Active pumps need energy to establish the ion gradients.
  • There is a single positive charge in the guanidino group of tetrodotoxin.
    • The tetrodotoxin molecule is too large to pass through a sodium channel, so the guanidino group is likely to bind to it.
  • The channel is blocked.
  • Ion-channel blocking molecules can cause paralysis by disrupting electrical activity in the nervous system.
    • The snail toxins can be poisonous at low concentrations.
    • Such toxins could be useful for identifying and labeling new types of ion channels and for investigations of the channels' mechanisms of action.
  • This is a very important concept.
    • Let's take a look at the channels.
  • Na+ concentration can't be "sensed" by the cell when the sodium channels are closed, and there is no pathway by which Na+ ion could diffuse to adjust their concentrations toward equilibrium values.
    • A small number of the voltage-gated sodium channels open when the action potential is only 20 mV.
    • The opening of only a few channels causes a small initial increase in the sodium permeability, which causes a further increase in the membrane potential and more channels to open.
    • More and more channels are opened until the signal from the sodium ion peaks within 1 ms. All of the sodium channels will close after 1.5 ms from the initial triggering event.
    • During the short time that it is open, each channel only allows the passage of a small amount of Na+).
  • An initial triggering event can be amplified as many channels become involved, and the nerve cell can recover quickly and transmit a new impulse every few milliseconds, if the ability to generate a signal using only a small number of ion is taken into account.
  • It needs repolarization to return to a closed state.
    • Since BTX keeps the sodium channels open after depolarization, it blocks the transition from open to inactivated state.

chloride ion will flow into the cell

  • The action potential of the depolariza tion causes the chloride flux to be inhibitory.
  • There is a high concentration of lactose in the inner volume of the vesicles.
    • The binding of Lactose to the inner face of the permease would be followed by the binding of a protons.
    • Both sides would never give up.
    • Lactose and the proton will leave the permease because of the low concentration on the outside.
    • The uphill flux of protons will be driven by the downhill flux of Lactose.
  • For proper nerve activity, the change in permeability caused by the opening of channels must be short-lived.
    • It is important to remove the source of stimulation in order to close the channels.
    • Once initiated, the nerve impulse moves on and the postsynaptic membrane must return to its resting state in order to be ready to receive and propagation another signal.
  • Acetylcholinesterase has a similar mechanism to the serine proteases.
    • As with chymotrypsin and trypsin, the active site of acetylcholinesterase has serine.
    • The mechanism will involve the use of acyl and tetrahedral intermediates in which the substrates are bonded to the active-site Ser.
  • The Ser OH group gives a carbonyl group that acts as a base and accepts H+).
    • The acetyl group will be left to join the Ser in the acyl-enzyme intermediate.
    • In the second half of the reaction, water will act as a nucleophile to attack the acyl enzyme.
    • The free enzyme will be regenerated when the second product leaves.
    • The process can be repeated.
  • After the application of the toxin, the currents from these channels are completely stopped for about 60 s.
  • At the end of the first set of record ings in part A, the ASIC1a channels are starting to recover.
  • The estimate is based on the logarithmic scale.
  • The channels with the bV266M are open for longer.
    • There are possible explanations for the slower closing rate.
    • A tighter binding of acetylcholine could keep the channels open longer.
  • The normal rate of release of chyln could be delayed by the mutation, which could slow the transition from the open state to the closed state.
  • The rate of indole transport is determined by the concentration of indole.
    • This finding shows that indole can diffuse without a specific mechanism for transporting it.
    • By constrast, the rate of transport reaches a saturation point with no further rate increase.
    • There is a correlation between the finding for glucose and the fact that it would bind to a specificProtein and then be transported across the Membrane.
    • The transport rate would go up when all of the sites are occupied by the same molecule.
    • The inhibition of glucose transport by ouabain suggests that it requires energy and that it may be linked to the transport of Na+ or K+.