An overview of the subject will help you understand organic structures that appear in relation to other topics on the exam. Some high school and college teachers teach this material. This chapter should be considered a bonus chapter.

The study of the chemistry of carbon is called organic chemistry. Most of the compounds containing carbon are classified as organic compounds. There are only a few carbonates and cyanides that are classified as inorganic. In the 19th century, it was thought that all organic compounds had to be produced by living organisms, but this idea was proven wrong when German chemist Friedrich Wohler produced the first organic compound from starting materials. Many organic compounds found in nature have been synthesised by chemists since that time. It is carbon's characteristic of bonding strongly to itself and to other elements in long, complex chains and rings that gives it the ability to form the many diverse and complex compounds needed to support life.

The AP exam does not include equations specific to this chapter.

Alkanes are part of a family of organic compounds. The simplest of organic compounds, these hydrocarbons are very important to our society as fuels and raw materials for chemical industries.

We heat our homes and run our cars through the fire. Paints, plastics, and pharmaceuticals are often made from hydrocarbons.

Saturated hydrocarbons are bonds to the maximum number of other atoms. These alkanes may be straight-chained hydrocarbons, in which the carbons are sequential bonded; branched hydrocarbons, in which another hydrocarbon group is bonding to the backbone; or they may be cyclic, in which the hydrocarbon is composed entirely or partially of a ring system. Table 18.1 shows the first 10 straight-chained alkanes.

There can be more carbon units in a chain than shown in Table 18.1, which allows us to study the naming of alkanes.

The longest carbon chain in the structural formula is the basis for naming alkanes.

There is a continuous carbon chain in the compound. The base name of the alkane will be provided by this.

Adding the names of the branches in front of the base name will modify it. Methane becomes propyl, propane becomes propyl, and so on. List them chronologically if there is more than one branch.

The location number indicates the position where the substituent is attached to the chain. The numbers are assigned by the number of carbons in the base hydrocarbon. The lowest sum of location numbers for the substituent groups can be found at the end. If you want to separate the location number from the name, place it in front of the substituent name.

The Greek prefixes are not considered in the arrangement.

A part of the base name is the last substituent group.

You may be able to learn the name of substituted alkanes by studying Figures 18.1 and 18.2.

Isomers are compounds with the same formulas but different ones. This applies to a different arrangement of carbon atoms. Each structure has the same number of carbons and hydrogens. The way the carbons are bond is not different.

One of the most common mistakes a chemistry student makes is writing an organic structure with a carbon atom that has fewer than four bonds.

There is a practice problem.

Pick the longest chain first. This is bold-faced in the diagram. This is an alkane because the carbons are attached by single bonds. The longest chain has nine carbons.

Next, the longest chain should be numbered from one end to the other with the lowest number going to the branches.

Do not change the numbers after they have been assigned.

The carbon atoms that are not part of the main chain are branches. You can circle the carbon atoms in the branches. There are three branches in this example. There are two groups of one carbon. The branch has two carbons and is an ethyl group. The branches are arranged in chronological order. The two groups are called dimethyl. Each branch's position is indicated by a number that is already determined for the main chain. Even if the branch is the same as the one already used, it must have its own number.

There are two ways to separate numbers from letters.

optical isomerism is a type of isomerism. The molecules are said to be able to light up either the left or right. A compound that has a carbon atom with four different groups attached to it will be active.

If chemistry students had to learn the properties of millions of pounds of organic material, it would be impossible. It is possible that having certain arrangements of atoms in an organic molecule causes those molecule to react in a simi lar fashion. The same types of reactions are experienced by ethyl alcohol, CH3-OH, and methyl alcohol. The reactive part of the molecule is the -OH group. These groups are called functional. One can learn the properties of functional groups instead of learning the proper ties of individual molecules.

There are two functional groups in our study of the simple hydrocarbons. A double bond is carbon-to-carbon. A carbon-to-carbon double bond is called alkenes. Alkanes and alkenes are very similar to each other. The position of the double bond has the lowest location number because the carbon backbone of the base hydrocarbon is numbered.

A carbon-to-carbon triple bond is one of the hydrocarbon functional groups. A triple bond is found in hydrocarbons. These hydrocarbons have a double or triple bond.

The major functional groups are shown in Table 18.2.

In the introduction to this chapter, we mentioned that carbon can bond to itself in long and complex chains.

Nature has macromolecules. There are a few macromolecules that occur naturally. The diversity of compounds needed to make up a tree or a human being is provided by carbon's ability to form large, complex molecule. Many of the macromolecules we use every day are created in the lab by chemists. Polyvinylchloride is a synthetic macromolecule. Mono mers are joined together in the process of polymerization. These synthetic fabrics have become a part of our society. The complexity of carbon compounds can be seen in our modern society.

The concepts of organic chemistry would probably be applied in an experiment.

Make sure that every carbon has at least four bonds.

The sum of all location numbers should be as small as possible when naming alkanes.

When naming branched alkanes, be sure to consider the branches. The carbon atoms in a horizontal line aren't always the longest chain.

When naming identical substituents on the longest carbon chain, be sure to use repeating location numbers.

You can use these questions to improve your understanding of chemistry. This section contains the same types of questions as those found on the AP exam, even though organic chemistry won't be tested on the exam. There are 10 multiple-choice questions. There is a long free-response question. Follow the instructions to practice pacing yourself.

You can't use a calculator. The periodic table and equation sheet can be found at the back of the book.

CnH2n is the formula for the following compounds.

The mass of the alkene teristic of a carboxylic acid is the same as the charac moles of water.

Drawing the structures will help you to recognize the correct answer.

In general, organic bases are amines.

Answer C is not true. It is similar to A, but two of N. An ether has an oxygen atom and two carbon atoms.

The 2CH3 groups are the same.

An aldehyde has oxygen in it.

A is an alcohol, B is an aldehyde and C is an ether.

A general formula is dissolved in water and attached to an oxygen base. A is neutral.

C is an acid.

A base is an amine, which is Oxygen double D.

There is an organic group attached to the organic bases. An ether has a certain amount of oxygen. There is a hydro single-bonded to two carbons in B. The carbonyl group has an atom attached to it. There is an oxygen atom at the end of a chain in C.

A carbon atom with four bonds is not an alcohol or an aldehyde.

All organic compounds burn.

This is a carboxylic acid because of the OH group attached to a carbonyl group.

You have 20 minutes to answer the questions. You can use the tables in the back of the book.

C6H14 has a mass of 86.17 g mol-1.

Write a balanced chemical equation. The reaction produces carbon dioxide, CO2, and water Vapor, H2O.

The carbon dioxide should be stored in a container of 20.0 liters.

Below is the structural formula of one of the isomers. The structural formula of any of the other isomers. All carbon atoms and hydrogen atoms should be shown.

An organic base group and an organic acid group are present in the body. Two groups are interacting with each other. N+H3 CH2COO- is a better form of the simplest natural amino acid, NH2CH2COOH.

Go through the Lewis structure for glycine and review the knowledge you need to score high. You only need to show one form if resonance is possible.

The materials in these questions depend on basic AP chemistry knowledge, which is why this chapter is valuable.

If you have more than one, but not all, of the elements balanced, give yourself 1 point.

The set-up and correct answer requires a negative sign in the answer. Give yourself 1 point if the set-up is not perfect.

There is an extra significant figure in this answer. The mole ratio is related to the balanced equation. You won't be punished for an incorrect equation again.

You have to give yourself 2 points for the correct answer. If you did everything correctly, give yourself 1 point.

Give yourself a maximum of 4 points for each correct answer. There is no bonus points for additional answers.

The compounds are 2-methylpentane, 3-methylpentane, 2, 2-dimethylbutane, and 2,3-dimethylbutane. They are the only isomers. You have redrawn one of these if you think you have another isomer. If you can name your answer, you can see if it matches one of the names.

There is a chance for 10 points. If you don't have the correct number of significant figures, subtract 1 point.

The materials in these questions depend on basic AP chemistry knowledge, which is why this chapter is valuable.

A correct Lewis structure is around the nitrogen and carbon atoms. You get 1 point for a correct Lewis structure.

The formal charge for an atom is nonbonding electrons.

The charges for the left structure are in the table. Simply reverse the lines for Oa and Ob.

If the total of all the formal charges is zero, you get 1 point for a correct set of charges.

There are points that can be scored.